![]() So from 0 degrees you take (x, y) and make them negative (-x, -y) and then you've made a 180 degree rotation. When you rotate by 180 degrees, you take your original x and y, and make them negative. If you have a point on (2, 1) and rotate it by 180 degrees, it will end up at (-2, -1) One of the simplest and most common transformations in geometry is the 180-degree rotation, both clockwise and counterclockwise. We do the same thing, except X becomes a negative instead of Y. If you understand everything so far, then rotating by -90 degrees should be no issue for you. Our point is as (-2, -1) so when we rotate it 90 degrees, it will be at (1, -2)Īnother 90 degrees will bring us back where we started. What about 90 degrees again? Same thing! But remember that a negative and a negative gives a positive so when we swap X and Y, and make Y negative, Y actually becomes positive. Our point is at (-1, 2) so when we rotate it 90 degrees, it will be at (-2, -1) Provide a valid argument, using geometry theorems or postulates, to validate Andres claim. ![]() What if we rotate another 90 degrees? Same thing. A counter-clockwise rotation of 90 degrees about the origin. So from 0 degrees you take (x, y), swap them, and make y negative (-y, x) and then you have made a 90 degree rotation. ![]() When you rotate by 90 degrees, you take your original X and Y, swap them, and make Y negative. To rotate a shape we need: a centre of rotation an angle of rotation (given in degrees). If you have a point on (2, 1) and rotate it by 90 degrees, it will end up at (-1, 2) Rotations are transformations that turn a shape around a fixed point. Here is an easy to get the rules needed at specific degrees of rotation 90, 180, 270, and 360. In case the algebraic method can help you: Having a hard time remembering the Rotation Algebraic Rules. ![]()
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